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If the r.m.s. value of A.C. is I("rms") ...

If the r.m.s. value of A.C. is `I_("rms")` then peak to peak value is –

A

`l_rms = pi l_(0)`

B

`l_(rms) = sqrt(2)" "l_(0)`

C

`l_(rms) = (l_(0))/(pi)`

D

`l_(rms) = l_(0)/sqrt(2)`

Text Solution

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The correct Answer is:
D
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