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The electric current in a circuit is giv...

The electric current in a circuit is given by I = 3 sin `omegat + 4 cos omegat.` The rms current is

A

`(5)/sqrt(2)`

B

5

C

`(4)/sqrt(2)`

D

`(3)/sqrt(2)`

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The correct Answer is:
To find the RMS (Root Mean Square) current from the given equation of electric current \( I = 3 \sin(\omega t) + 4 \cos(\omega t) \), we will follow these steps: ### Step 1: Identify the given current equation The current is given as: \[ I = 3 \sin(\omega t) + 4 \cos(\omega t) \] ### Step 2: Rewrite the equation in standard form The standard form of an AC current is: \[ I = I_0 \sin(\omega t + \phi) \] where \( I_0 \) is the peak current and \( \phi \) is the phase angle. To rewrite the given equation in this form, we need to find \( I_0 \) and \( \phi \). ### Step 3: Find the peak current \( I_0 \) We can express \( I \) as: \[ I = R \sin(\omega t + \phi) \] where \( R \) is the resultant amplitude. We can find \( R \) using the coefficients of sine and cosine: \[ R = \sqrt{(3)^2 + (4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] Thus, \( I_0 = R = 5 \). ### Step 4: Calculate the RMS current The RMS current is given by the formula: \[ I_{\text{rms}} = \frac{I_0}{\sqrt{2}} \] Substituting the value of \( I_0 \): \[ I_{\text{rms}} = \frac{5}{\sqrt{2}} \text{ A} \] ### Step 5: Final answer Thus, the RMS current is: \[ I_{\text{rms}} = \frac{5}{\sqrt{2}} \text{ A} \]
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