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According to Ampere's circuital law...

According to Ampere's circuital law

A

`oint bar(B). bar(dI) - mu_(0) (i_(C ) + epsilon_(0) (d phi_E)/(dt))`

B

`oint bar(B). bar(dI) = mu_(0) epsilon_(0) (d phi_E)/(dt)`

C

`oint bar(B). bar(dI) = mu_(0) epsilon_(0) i`

D

`oint bar(B). bar(dI) = mu_(0)(i_C (d phi_E)/(dt) +i_(O) ) `

Text Solution

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The correct Answer is:
A
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State Amperes circuital law.

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Knowledge Check

  • Maxwell's modified form of Ampere's circuital law is

    A
    `ointvecB.vec(ds)=0`
    B
    `ointvecB.vec(dl)=mu_(0)I`
    C
    `ointvecB.vec(dl)=mu_(0)I+(1)/(epsilon_(o))(dq)/(dt)`
    D
    `ointvecB.vec(dl)=mu_(0)I+mu_(0)epsilon_(o)(d oint_(E))/(dt)`

  • Which of the following ares assorciated with Maxwell ? a. Displacement current (b) Unification of the laws of elecriciry and magnestism (c) Development of Ampere's circuital law (d) Velocity distribuation of molecues in gas (e) Modification of Ampere's law

    A
    a,de
    B
    a,b,d,e
    C
    b,c
    D
    All of these

  • Assertion: Ampere’s circuital law is independent of Biot-Savart’s law. Reason: Ampere’s circuital law can be derived from the Biot-savart’s law.

    A
    Assertion is correct, reason is correct, reason is a correct explanation for assertion.
    B
    Assertion is correct, reason is correct, reason is not a correct explanation for assertion
    C
    Assertion is correct, reason is incorrect
    D
    Assertion is incorrect, reason is correct

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