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An electromagnetic wave going through va...

An electromagnetic wave going through vacuum is described by
` E= E_0 sin(kx- omega t), B=B_0sin(kx-omega t)`.
Then

A

`E_0 k = B_0 omega`

B

`E_0 B_0 = omegak`

C

`E_0 omega = B_0 k`

D

` E_0 B_0 = (omega)/(k)`

Text Solution

Verified by Experts

The correct Answer is:
A
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