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The polariser and analyser are inclined ...

The polariser and analyser are inclined to each other at `60^(@)`. The intensity of polarised light emerging from polariser is I. The intensity of the unpolarised light incident on the polariser is

Text Solution

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Let `l_0` be the intensity of the unpolarized light incident on the polarizer. Then the intensity of the polarized light transmitted through it is `l_0//2`
Using Malus law, the intensity of the light transmitted through the analyser is `(l_0/2) cos^2 60^@=l_0/8`
According to the given question `l_0/8=1`
`therefore l_0=8l`
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