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Light of wavelength 589.3nm is incident ...

Light of wavelength `589.3nm` is incident normally on the slit of width `0.1mm`. What will be the angular width of the central diffraction maximum at a distance of `1m` from the slit?

A

`0.68^@`

B

`0.34^@`

C

`2.05^@`

D

`6.75^@`

Text Solution

Verified by Experts

`theta`( central)=`(2 lamda)/d=(2 times 589.3 times 10^-9)/(0.01 times 10^-3) times 180^@/pi=6.75^@`
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