Home
Class 12
PHYSICS
The threshold frequency of a material is...

The threshold frequency of a material is `2xx10^14` Hz. What is its work function in eV ?

Text Solution

Verified by Experts

` phi _(0) = hv_(0) 6.62 xx 10^(-34) xx 2 xx 10^(14) J`
` = 1.324 xx 10^(-19) J`
` = (1.324 xx 10^(-19))/(1.6 xx 10^(-19)) eV = 0.8275 eV `
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    AAKASH INSTITUTE|Exercise Try Yourself|15 Videos

  • ALTERNATING CURRENT

    AAKASH INSTITUTE|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|34 Videos

  • ATOMS

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION J (Aakash Challengers )|4 Videos

Similar Questions

Explore conceptually related problems

The threshold frequency for a photosensitive metal is 3xx10^(14)Hz . The work function of the metal is approximately equal to [h=6.66xx10^(-34)Js]

The light radiation of wavelength 6000 Å falls on a metal . The threshold frequency of a metal surface is 4 xx 10^(14) Hz . The maximum velocity of the emitted photoelectrons is

The threshold freqeuncy of a certain metal is 3.3xx10^(14)Hz . If light of frequency 8.2xx10^(4)Hz is incident on the metal, predict the cut off voltage for photoelectric emission. Given Planck's constant, h=6.62xx10^(-34)Js .

Calculate the threshold frequency of a photon from a photosensitive surface of work function 0.2 eV . Take h=6.6xx10^(-34)Js.

The minimum frequency for photoelectric effect on a metal is 7xx10^(14) Hz, Find the work function of the metal.

If a photoemissive surface has a threshold frequency of 3 xx 10^(14) Hz, calculate the energy of the photons in eV.

If a photoemissive surface has a threshold frequency of . 6 xx 10^(14)Hz , calculate the energy of the photons in eV. Given h=6.6 xx 10^(-34)Js .