if the speed of photoelectrons is `10^4` m/s, what should be the frequency of the incident radiation on a potassium metal ? Given : Work function of potassium =2.3 eV
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` E = K_(max) + phi` ` = 1/2 mv^(2) + phi` ` = 1/2 xx 9 xx 10^(-31) x (10^(4))^(2) + 2.3 xx 1.6 xx 10 ^(-19)` ` = 4.5 xx 10^(-23) J + 3.68 xx 10 ^(-19)` ` = 3 . 68 xx 10^(-19) J ` ` V = (E)/(h) = (3.68 xx 10 ^(-19))/(6.63 xx 10^(-34)) Hz = 0.56 xx 10^(15) Hz ` .
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