When light of wavelangth `4000 Å` is incident on a barium emitter , emitted photo electrons in a transverse magnetic field strength ` B = 5.2 xx 10^(-6)` T moves in a circular path . Find the radius of the circle . Given work function of barium is 2.5 eV and mass of electron is ` 9.1 xx 10^(-31)` kg . ` e = 1.6 xx 10^(-19) C , h = 6.6 xx 10^(34) Js ` .
Text Solution
AI Generated Solution
To find the radius of the circular path of emitted photoelectrons in a transverse magnetic field, we will follow these steps:
### Step 1: Calculate the Energy of the Incident Photons
The energy of the incident photons can be calculated using the formula:
\[
E = \frac{hc}{\lambda}
\]
Where:
...
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Calculate the strength of the transverse magnetic field required to bend all photoelectorns within a circle of radius 50 cm, when light of wavelength 4000Å is incident on a barium emitter. Work function of barium is 2.5eV. Given, m_e=9.1xx10^(-31)kg, e=1.6xx10^(-19)C, h=6.6xx10^(-34)Js.
Calculate the energy in MeV equivalent to the rest mass of an electron . Given that the rest mass of an electron , m=9.1 xx 10^(-31) kg , 1MeV = 1.6 xx 10^(-13) J and speed of light , c= 3 xx 10 ^(8) ms ^(-1) .
In a photocell bichromatic light of wavelength 2475 Å and 6000 Å are incident on cathode whose work function is 4.8 eV . If a uniform magnetic field of 3 xx 10^(-5) Tesla exists parallel to the plate , the radius of the path describe by the photoelectron will be (mass of electron = 9 xx 10^(-31) kg )
An electron beam has a kinetic energy equal to 100 eV . Find its wavelength associated with a beam , if mass of electron = 9.1 xx 10^(-31) " kg and 1 eV " = 1.6 xx 10^(-19) J . (Planks's constant = 6.6 xx 10^(-34) J-s)
An electron is accelerated by a potential difference of 12000 volts. It then enters a uniform magnetic field of 10^(-3)T applied perpendicular to the path of electron. Find the radius of path. Given mass of electron =9xx10^(-31)kg and charge on electron =1.6xx10^(-19)C
If de Broglie wavelength of an electron is 0.5467 Å, find the kinetic energy of electron in eV. Given h=6.6xx10^(-34) Js , e= 1.6xx10^(-19) C, m_e=9.11xx10^(-31) kg.
What is the uncertainty in velocity of an electron if the uncertainty in its position is 10^(-10) m ? Mass of the electron is 9.1 xx 10^(-31) kg and h = 6.6 xx 10^(-34) m^(2) s^(-1) ?
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