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If de Broglie wavelength of an electron ...

If de Broglie wavelength of an electron is 0.5467 Å, find the kinetic energy of electron in eV. Given `h=6.6xx10^(-34)` Js , e=`1.6xx10^(-19)` C, `m_e=9.11xx10^(-31)` kg.

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` E_(k) = (1)/(2) (h^(2))/(mlambda^(2)) = (1)/(2) xx ((6.6xx 10^(-34))^(2))/(9.11xx 10^(-31) xx (05467 xx 10^(-10))^(2)) J `
` E_(k)" in eV " = (1)/(2) xx ((6.6xx 10^(-34))^(2))/((9.11xx 10^(-31)) xx (1.6xx 10^(-19))xx(05467 xx 10^(-10))^(2)) = 500 eV `
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