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When the mkomentum of a proton is change...

When the mkomentum of a proton is changed by an amount `p_(0)`, the corresponding change in the de-Broglie wavelength is found to be `0.25%`. Then, the original momentum of the proton was

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`lambda oo (1)/(p) rArr (Deltap)/(p) = - (Delta lambda)/(lambda) rArr (p_(0))/(p) = (0.25)/(100) rArr p = 400 p_(0) `
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