Home
Class 12
PHYSICS
A proton and and alpha - particle are ac...

A proton and and `alpha `- particle are accelerated through a potential difference of `100 V`. The ratio of the wavelength with the proton to that associated to that associated with an `alpha` - particle is

Text Solution

Verified by Experts

` lambda = (h)/(sqrt(2mQV))`
` rArr lambda oo (1)/(sqrt(mQ))`
` rArr (lambda_(p))/(lambda_(alpha)) = sqrt((m_(alpha) Q_(alpha))/(m_(p) xx Q_(p)))`
` = sqrt((4m_(p)xx 2Q_(p))/(m_(p) xx Q_(p)))`
` = 2sqrt(2)` .
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    AAKASH INSTITUTE|Exercise Try Yourself|15 Videos
  • ALTERNATING CURRENT

    AAKASH INSTITUTE|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|34 Videos
  • ATOMS

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION J (Aakash Challengers )|4 Videos

Similar Questions

Explore conceptually related problems

A proton and an alpha particle are accelerated through the same potential difference. The ratio of the wavelengths associated with the proton to that associated with the alpha particle is

A proton and an alpha -particle are accelerated through same potential difference. Find the ratio of their de-Brogile wavelength.

An alpha - particle is accelerated through a potential difference of 100 V. Its de-Broglie's wavelength is

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha -particle is

Find the de Broglie wavelength of an alpha particle accelerated through a potential difference of 100 V.

For an alpha particle , accelerated through a potential difference V , wavelength (in Å ) of the associated matter wave is

An alpha -particle and a proton are accelerated from rest through the same potential difference V. Find the ratio of de-Broglie wavelength associated with them.