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The de - Broglie wavelength of a neutron...

The de - Broglie wavelength of a neutron at `27 ^(@) C` is `lambda`. What will be its wavelength at `927^(@) C`?

A

`(lambda)/(2)`

B

`(lambda)/(3) `

C

`(lambda)/(4)`

D

`(lambda)/(9) `

Text Solution

Verified by Experts

The correct Answer is:
A
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