A proton and an alpha particle are accelerated through the same potential difference. The ratio of the wavelengths associated with the proton to that associated with the alpha particle is
A
2
B
`sqrt(2)`
C
4
D
`(1)/(2sqrt(2))`
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
ALTERNATING CURRENT
AAKASH INSTITUTE|Exercise Try Yourself|15 Videos
ALTERNATING CURRENT
AAKASH INSTITUTE|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|34 Videos
A proton and an alpha -particle are accelerated through same potential difference. Find the ratio of their de-Brogile wavelength.
A proton and and alpha - particle are accelerated through a potential difference of 100 V . The ratio of the wavelength with the proton to that associated to that associated with an alpha - particle is
An electron of mass m_e and a proton of mass m_p are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is
A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha -particle is
An electron and a proton are accelerated through the same potential difference. The ratio of their de-Broglie wavelengths will be
An electron and a proton are accelerated through the same potential difference. The ratio of their de broglic wavelengths will be
An alpha -particle and a proton are accelerated from rest through the same potential difference V. Find the ratio of de-Broglie wavelength associated with them.
For an alpha particle , accelerated through a potential difference V , wavelength (in Å ) of the associated matter wave is
AAKASH INSTITUTE-ALTERNATING CURRENT -Assignment (Section-J) (Aakash Chailengers Questions)
