Home
Class 12
PHYSICS
Electrons with de-Broglie wavelength lam...

Electrons with de-Broglie wavelength `lambda` fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

A

` lambda_(0) = (2mc lambda^(2))/(h) `

B

`lambda_(0) = (2h)/(mc)`

C

`lambda_(0) = (2m^(2) c^(2) lambda^(3))/(h^(2))`

D

`lambda_(0) = lambda `

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    AAKASH INSTITUTE|Exercise Try Yourself|15 Videos

  • ALTERNATING CURRENT

    AAKASH INSTITUTE|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|34 Videos

  • ATOMS

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION J (Aakash Challengers )|4 Videos

Similar Questions

Explore conceptually related problems

Eletrons with de- Broglie wavwlength lambda fall on the target in an X- rays tube . The cut off wavelength of the emitted X- rays is

Electrons with de - Brogli wavelengtyh lambda fall on the target in an X-ray tube.The cut off wavelength of the emitted Xrays is (a) lambda_0 = (2mclambda^2)/(h) (b) lambda_0 = (2h)/(mc) (c ) lambda_0 (2m^2 c^2 lambda^3)/(h^2) (d) lambda_0 = lambda

de-Broglie wavelength lambda is

The de Broglie wavelength lambda of a particle

The cut-off wavelength of an X-ray depends on

De Broglie wavelength lambda is proportional to

A photon sensitive metallic surface emits electrons when X-rays of wavelength lambda fal on it. The de-Broglie wavelength of the emitted electrons is (Neglect the work function of the surface, m is mass of the electron. H=Planck's constant. C= velocity of light)

An X-ray tube is operated at 20 kV. The cut off wavelength is