When a metallic surface is illuminated with radiation of wavelength `lambda`, the stopping potentials is V. If the same surface is illuminated with radiation of wavelength `2 lambda`, the stopping potential is `( V )/( 4)`. The threshold wavelength for the metallic surface is
A
` 3 lambda `
B
`4 lambda `
C
`5 lambda `
D
`(5)/(2) lambda `
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The correct Answer is:
A
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