A source `S_(1)` is producing `10^(15)` photons/s of wavelength `5000 Å` Another source `S_(2)` is producing `1.02 xx 10^(15)` photons per second of wavelength `5100 Å`. Then `("power of" `S_(2))/("power of" S_(1))` is equal to
A
`0.98 `
B
`1.00`
C
`1.02`
D
`1.04 `
Text Solution
Verified by Experts
The correct Answer is:
B
Topper's Solved these Questions
ALTERNATING CURRENT
AAKASH INSTITUTE|Exercise Try Yourself|15 Videos
ALTERNATING CURRENT
AAKASH INSTITUTE|Exercise Assignment (Section - A) ( Objective Type Questions ( One option is correct))|34 Videos
A source S_(1) is producing 10^(15) photons per second of wavelength 5000Ã… . Another source S_(2) is producing 1.02xx10^(15) Then, ("Power of" S_(2))//("Power of"S_(1)) is equal to
If a source of power 8 kW producees 10^(22) photons/ second, the wavelength of the radiation is
What is power (in watt) of a light source emitting 3.125 xx 10^(18) photons per second, while the wavelength of light is 620 nm ? (use hc = 12400 eVÅ )
The energy of a photon of wavelength 4000 Å is (use h=6.66xx10^(-34) J-s)
A monochromatic source of light operation at 200 W emits 4xx10^(20) photons per second. Find the wavelength of the light "(in" 10^(-7)m ).
The energy of a photon of light with wavelength 5000 Å is approximately 2.5 eV . This way the energy of an X - ray photon with wavelength 1 Å would be
For light of a wavelength 4000 Å, the photon energy is 2eV. For X rays of wavelength 1 Å, the photon energy will be
Calculate the wavelength of an ubraviolet wave , if its frequency is 12 xx 10^(16) cycles per second and c = 3 xx 10^(6) "in" s^(-1) ?
AAKASH INSTITUTE-ALTERNATING CURRENT -Assignment (Section-J) (Aakash Chailengers Questions)
