An electrono of mass m, when accelerated through a potential difference V, has de-Broglie wavelength `lambda`. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference, will be:
A
` lambda (M)/(m) `
B
`lambda (m)/(M) `
C
` lambda sqrt((M)/(m))`
D
` lambda sqrt((m)(M))`
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The correct Answer is:
D
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