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Dynamic mass of the photon in usual nota...

Dynamic mass of the photon in usual notations is given by

A

`(hv)/(c)`

B

`(h lambda)/(c)`

C

`(h)/( c lambda)`

D

`(h)/(cv)`

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The correct Answer is:
To find the dynamic mass of a photon, we can start from the relationship between energy, momentum, and mass in the context of relativity and quantum mechanics. Here’s a step-by-step solution: ### Step 1: Understand the relationship between energy and momentum of a photon The energy (E) of a photon is given by the equation: \[ E = h \nu \] where \( h \) is Planck's constant and \( \nu \) is the frequency of the photon. ### Step 2: Relate frequency to wavelength The frequency \( \nu \) can be related to the wavelength \( \lambda \) of the photon using the equation: \[ \nu = \frac{c}{\lambda} \] where \( c \) is the speed of light. ### Step 3: Substitute frequency in the energy equation Substituting the expression for frequency into the energy equation gives: \[ E = h \frac{c}{\lambda} \] ### Step 4: Use the relationship between energy and momentum The momentum \( p \) of a photon is given by: \[ p = \frac{E}{c} \] Substituting the expression for energy from Step 3, we have: \[ p = \frac{h c}{\lambda c} = \frac{h}{\lambda} \] ### Step 5: Relate momentum to mass In relativistic physics, the momentum of a particle is also related to its mass (m) and velocity (v) by the equation: \[ p = mv \] For a photon, which travels at the speed of light, we can express the mass in terms of momentum: \[ m = \frac{p}{c} \] ### Step 6: Substitute the expression for momentum Substituting the expression for momentum from Step 4 into the mass equation gives: \[ m = \frac{h/\lambda}{c} \] ### Final Expression Thus, the dynamic mass of the photon can be expressed as: \[ m = \frac{h}{\lambda c} \]
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