Calculate the retarding potential to be applied to an eklectron to de Broglie wavelength from 1.73 Å to 2.25 Å ?
A metal surface of work function 1.07 eV is irradiated with light of wavelength 332 nm . The retarding potential required to stop the escape of photo - electrons is
The kinetic energy of an electron with de - Broglie wavelength of 0.3 nanometre is
If a proton and electron have the same de Broglie wavelength, then
The velocity of an electron with de Broglie wavelength of 1.0 xx 10^(2) nm is:
An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 xx 10^(-2) nm, the potential difference is:
AAKASH INSTITUTE-ALTERNATING CURRENT -Assignment (Section-J) (Aakash Chailengers Questions)
