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What is the binding energy per nucleon i...

What is the binding energy per nucleon in `._2He^4`
Given , Mass of `._2He^4`=4.002604 amu
Mass of proton =1.007825 amu
Mass of neutron =1.008665 amu

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Mass defect =[2.01565+2.01733-4.002604]=0.030376 amu
Bindding energy `=(0.030376xx931)` MeV =28.28 MeV
`therefore` Binding energy per nucleon `=(28.28)/4=7.07` Mev
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