Binding energy of `""_2He^4 and ""_3Li^7` are 27.37 MeV and 39.3 MeV respectively. Which of the two nuclei is more stable ?

Explanation

To determine which of the two nuclei, Helium-4 (He-4) or Lithium-7 (Li-7), is more stable based on their binding energies, we will follow these steps:

### Step 1: Identify the given binding energies
- Binding energy of He-4: 27.37 MeV
- Binding energy of Li-7: 39.3 MeV

### Step 2: Calculate the number of nucleons in each nucleus
- Helium-4 has 4 nucleons (2 protons and 2 neutrons).
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