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20 MeV energy is released per fusion rea...

20 MeV energy is released per fusion reaction
`""_1H^2 +""_1H^2 to ""_2He^4 +""_0n^1`
Calculate the mass of `""_1H^2` consumed in a fusion reactor of power 1 MW in 1 day .

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Verified by Experts

`P =1 MW =10^6 W=10^6 Js^(-1)`
`t=1 "days" =24xx60xx60=86400 s`
`therefore` Energy released in one day `=pt=86400xx10^6J`
Energy released per fusion =20 MeV `=20 xx1.6 xx10^(-13)=3.2 xx10^(-12)J`
Mass of `""_1H^2` consumed in one fusion `(""_1H^2+""_1H^2)` =4u
`=4xx1/66 xx10^(-27)` kg
`=6.64 xx10^(-27)` kg
`=(6.64xx10^(-27))/(3.2 xx10^(-12))xx86400xx10^6`
`=1.79 xx10^(-4)` kg
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