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Calculate the energy released when three...

Calculate the energy released when three `alpha`-particle `(""_2He^4)` fuse to form a carbon `(""_6C^(12))` nucleus.
Given `m(""_2He^4)=4.002603` amu.

Text Solution

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`3 ""_2He^4 to ""_6C^(12)+Q`
`therefore Q=m (3 ""_2He^4)-m(""_6C^(12))=12.0078-12=0.007809`
`therefore` Energy released `=0.007809 xx931 MeV =7.27` MeV
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