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The decay constant of radio isotope is l...

The decay constant of radio isotope is `lambda`. If `A_(1) and A_(2)` are its activities at times `t_(1) and t_(2)` respectively, the number of nuclei which have decayed during the time `(t_(1)-t_(2))`

A

`A_1t_1-A_2t_2`

B

`A_1-A_2`

C

`(A_1-A_2)//lambda`

D

`lambda(A_1-A_2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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