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.(90)Th^(232) to .(82)Pb^(208). The numb...

`._(90)Th^(232) to ._(82)Pb^(208)`. The number of `alpha and beta-"particles"` emitted during the above reaction is

A

`4alpha,7beta`

B

`4alpha,1beta`

C

`8alpha,7beta`

D

`4alpha,4beta`

Text Solution

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The correct Answer is:
B
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