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A tansmitting antenna at the top of a tower has a height 32 m and that of the receiving antenna is 50 m. What is the maximum distance between them for satisfactory communication in line of sight mode ? Given radius of earth is `6.4 xx 10^(6) m`.

Text Solution

Verified by Experts

`d= sqrt(2Rh_(T)) + sqrt(2Rh_(R))`
`d= sqrt(2 xx 6.4 xx 10^(6) xx 32) + sqrt(2 xx 6.4 xx 10^(6) xx 50)`
`=64 xx 10^(2) xx sqrt10 + 8 xx 10^(3) xx sqrt10m`
`= 144 xx 10^(2) xx sqrt10m = 45.5 km`
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