The distance between the origin and the tangent to the curve `y=e^(2x)+x^2` drawn at the point `x=0` is

Find the distance between the point (1, 1) and the tangent to the curve y = e^(2x) + x^(2) drawn from the point x = 0.

The distance betwcen the point (1, 1) and the tangent to the curve y= e^(2x) +x^(2) drawn from the point x =0 is

The distance between the origin and the normal to the curve y=e^(2x)+x^(2) at x=0 is

The distance between the point (1 1) and the normal to the curve y=e^(2x)+x^(3) at x=0 is

The tangent to the curve y=e^(2x) at the point (0,1) meets X-axis at

The tangent to the curve y = e^(2x) at the point (0,1) meets x - axis at :

Find the equation of the tangent to the curve y={[x^(2)sin(1)/(x),x!=0 at the origin 0,x=0