In a given network the equivalent capacitance between A and B is `[C_(1)=C_(4)=1muF,C0_(2)=C_(3)=2muF]`

Consider the network of capacitors as shown in the figure. Find equivalent capacitance between points A and C. Assume C_(1)=1muF, C_(2)=0.5muF and C_(3)=1muF .

In the given network ,the value of C ,so that an equivalent capacitance between A and B is 3 muF ,is

In the network of capacitors given ahead. Find the effective capacitance between point P and Q If C_(1)=C_(2)=C_(3)=C_(4)=4 muF Value is not given C_(1) and C_(2)

The equivalent capacity between A and B in the given circuit is (C_(1) =4muF,C_(2)=12 muF,C_(3)=8muF , C_(4)=4muF,C_(5)=8muF)

Calculate the effective capacitance between a and b from the figure given below: C_(1)=C_(3)=100muF, C_(2)=C_(4)=200muF .

Find the capacitance C in the circuit shown in figure if the equivalent capacitance between points A and B is 1muF .

In the network of capacitors shown in figure 6.14 find the equivalent capacitance between a and b. Take C=2 muF

In the figure given below, find the, (a) equivalent capacitance of the network between points A and B. Given: C_1 = C_5 = 4muF , C_2 = C_3 = C_4 = 2 muF (b) maximum charge supplied by the battery, and (c) total energy stored in the network