80^(@)cos20^(@)-cos80^(@)sin20^(@)=(sqrt(3))/(2)

sin20^(@)*cos40^(@)+cos20^(@)*sin40^(@)=(sqrt(3))/(2)

Prove that (i) sin 70^(@) cos 10^(@) -cos 70^(@) sin 10^(@) =(sqrt(3))/(2) (ii) cos 50^(@) cos 10^(@) -sin 50^(@) sin 10^(@) =(1)/(2) (ii) cos 80^(@) cos 20^(@) + sin 80^(@) sin 20^(@) =(1)/(2) (iv) sin 36^(@) cos 9^(@) + cos 36^(@) sin 9^(@) =(1)/(sqrt(3))

(2cos40^(@)-cos20^(@))/(sin20^(@))

(2cos40^(@)-cos20^(@))/(sin20^(@))

(2cos40^(@)-cos20^(@))/(sin20^(@))=?

Simplify be reducing to a single term : sin 80^(@) cos 20^(@) - cos 80^(@) sin 20^(@).

cos 20^(@) cos 40^(@) cos 80^(@)=

Prove that,sin20^(@)sin40^(@)sin80^(@)=(sqrt(3))/(8)

Prove that sin20^(@)sin40^(@)sin80^(@)=(sqrt(3))/(8)

Prove that: sin20^(@)sin40^(@)sin80^(@)=(sqrt(3))/(8)