[" Thing "/_ABC=80^(@)" and "],[1:BD=8cmAD=4cm" ,"],[F^(5)o.]

In the figure beside, /_ABC=90^(@) and BDbotAC . If BD=8cm and AD=4cm , then find the length of CD .

In DeltaABC , /_ABC=90^(@) and BDbotAC , if BD=8cm and AD=5cm , then calculate the length of CD .

In the adjoining figure, /_ABC=90^(@) and BDbotAC . If AB=5.7cm , BD=3.8cm , CD=5.4cm , then find the length of BC .

In the given figure, angle ABC=90^(@) and BD bot AC . If BD=8 cm, AD=4 cm find CD.

In Delta ABC , /_ ABC = 90^(@) , BD _|_ AC . If BD = 8 cm , AD = 4 cm , find CD .

It the following figure, /_ ABC = 90^(@) and BD _|_ AC . If AD = 8 cm , CD = 2 cm, then the length of BD is :

In Fig.4.139,/_ABC=90o and BD perp AC If BD=8cm,AD=4cm, find CD( FIGURE )

In ABC, angleABC=90^(@), BD bot AC . If BD = 8 cm , AD = 4 cm, find CD and AB.

In the given figure, angle ABC=90^(@) and BD bot AC . If AB=5.7 cm, BD=3.8 cm and CD =5.4 cm , find BC.

Delta ABC is a right angled triangle where angle B = 90^@ " and " BD bot AC . If BD = 8 cm , AD = 4 cm , then CD is ………..