[" The lines "(x+4)/(3)=(y+6)/(5)=(z-1)/(-2)" and "3x-2y+z+5=0=2x+3y+4z-k" are coplanar,then the value of "],[k" is "]

Prove that the lines (x+4)/3=(y+6)/5=(z-1)/(-2) and 3x-2y+z+5=0=2x+3y+4z-4 are co-planar.

If the lines (x+4)/(3)=(y+6)/(5)=(z-1)/(-2) and 3x-2y+z+5=0=2x+3y+4z-k are coplanar,then k=(a)-4(2)3(3)2(4)4 (5)1

The (x+4)/(3) = (y+6)/(5) = (z-1)/(-2) and 3x - 2y + z+5 =0 = 2x + 3y + 4z -k are coplanar for k is equal to

If the lines (x+4)/3=(y+6)/5=(z-1)/(-2) and 3x-2y+z+5=0=2x+3y+4z-k are coplanar, then k= (a) -4 (2) 3 (3) 2 (4) 4 (5) 1

If the lines (x-2)/(1)=(y-4)/(4)=(z-6)/(k) and (x+1)/(3)=(y+3)/(5)=(z+5)/(7) are coplanar, then the value of k is

If the lines (x+1)/(2) =(y-1)/( 1) =(z+1)/(3) and (x+2)/(2) =( y-k)/(3) =(z)/(4) are , coplanar , then the value of k is

If the lines (x+1)/(2)=(y-1)/(1)=(z+1)/(3)and(x+2)/(2)=(y-k)/(3)=(z)/(4) are coplanar, then the value of k is

The lines (x-1)/(2)=(y)/(-1)=(z)/(2) and x-y+z-2=0=lambda x+3z+5 are coplanar for lambda

If the lines (x-2)/(1)=(y-3)/(1)=(z-4)/(-k) and (x-1)/(k)=(y-4)/(2)=(z-5)/(1) are coplanar, then find the value of k.