रेखाओं `(x+2)/8=(y-1)/-5=(z+1)/2` और `(x-3)/2=(y-5)/-3=(z-6)/2` के मध्य लघुतम दुरी ज्ञात कीजिये।

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

यदि (x/3+1,y-2/3) = (5/3,1/3) हो, तो x और y का माना ज्ञात , कीजिये।

Show that the lines : (i) (x -5)/(7) = (y + 2)/(-5) = (z)/(1) " " and (x)/(1) = (y)/(2) = (z)/(3) (ii) (x - 3)/(2) = (y + 1)/(-3) = (z - 2)/(4) and (x + 2)/(2) = (y - 4)/(4) = (z + 5)/(2) are perpendicular to each other .

If Q is the image of the point P (2,3,4) under the reflection in the plane x-2y+5z=6 then the equation of the line PQ is a) (x-2)/(-1)= (y-3)/2= (z-4)/5 b) (x-2)/(1)= (y-3)/(-2)= (z-4)/5 c) (x-2)/(-1)= (y-3)/(-2)= (z-4)/5 d) (x-2)/(1)= (y-3)/(2)= (z-4)/5

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1) (x+3)/3=(y-5)/1=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/5 (3) (x-3)/3=(y+5)/1=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/5

The image of the line (x-1)/(3)=(y-3)/(1)=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1)(x+3)/(3)=(y-5)/(1)=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/(5) (3) (x-3)/(3)=(y+5)/(1)=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/(5)

Statement 1: The lines (x-1)/1=y/(-1)=(z+1)/1 and (x-2)/2=(y+1)/2=z/3 are coplanar and the equation of the plnae containing them is 5x+2y-3z-8=0 Statement 2: The line (x-2)/1=(y+1)/2=z/3 is perpendicular to the plane 3x+5y+9z-8=0 and parallel to the plane x+y-z=0

Statement 1: The lines (x-1)/1=y/(-1)=(z+1)/1 and (x-2)/2=(y+1)/2=z/3 are coplanar and the equation of the plnae containing them is 5x+2y-3z-8=0 Statement 2: The line (x-2)/1=(y+1)/2=z/3 is perpendicular to the plane 3x+5y+9z-8=0 and parallel to the plane x+y-z=0