If the normal to the curve `y=f(x)` at the point `(3,4)` makes an angle `(3pi)/4` with the positive x-axis, then `f'(3)=` (a) `-1` (b) `-3/4` (c) `4/3` (d) `1`

If the normal to the curve y =f(x) at the point (1, 2) makes an angle 3pi//4 with the positive x-axis, then f'(1) is

If the normal to the curve y=f(x) at the point (3,4) makes an angle (3 pi)/(4) with the positive x-axis,then f'(3)=(a)-1(b)-(3)/(4) (c) (4)/(3)(d)1

If the normal to curve y = f (x) at the point (3,4) makes an angle (3pi)/(4) with positive x-axis then f'(3) equals:

If the inclination of the normal to the curve y=f(x) at the point (5,6) makes an anlge of (2pi)/(3), then f'(5)=

If the normal to y=f(x) makes an angle of.(pi)/(4) in anticlockwise direction with positive y- axis at (1,1), then f'(1) is equal to

A line tangent to the graph of the function y=f(x) at the point x= a forms an angle (pi)/(3) with the axis of Abscissa and angle (pi)/(4) at the point x=b then int_(a)^(b)f'(x)dx is

The distance of the point (-3,4) from the x-axis is : 3 (b) -3 (c) 4 (d) 5

The normal to the curve x^(2)=4y passing (1,2) is (A) x+y=3 (B) x-y=3 (D) x-y=1

If the area bounded by the curve y=f(x), x-axis and the ordinates x=1 and x=b is (b-1) sin (3b+4), then-