A `100 Omega` resistance is connected in series with a `4 H` inductor. The voltage across the resistor is, `V_(R ) = (2.0 V) sin (10^(3) t)`.
Find amplitude of the voltage across the inductor.

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is, V_(R ) = (2.0 V) sin (10^(3) t) . Find the inductive reactance

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is, V_(R ) = (2.0 V) sin (10^(3) t) . Find the expression of circuit current

A 100 Omega resistance is connected in series with a 4 H inductor. The voltage across the resistor is V_(R) = 2 sin (1000 t) V . The voltage across the inductors is

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expession of circuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expessinocircuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

A 100 Omega resistasnce is connected in series with a 4 H inductor. The voltage across the resistor is V_R=(2.0V)sin(10^3 rad//s)t : (a) Find the expession of circuit current (b) Find the inductive reactance (c) derive an expression for the voltage across the inductor,

The current through an inductor of 1H is given by i =3t sin t . Find the voltage across the inductor.

A coil of negligible resistance is connected in series with 90 Omega resistor across a 120 V - 60 Hz line. A voltmeter reads 36 V across the resistance. Find the voltage across the coil and Inductance of the coil