[1.x+y=3],[4x-3y=26]

x + y = 3, 4 x - 3y = 26 .

The solutions of pair of linear equations x+y=3 and 4x-3y=26,will be:

4x-2y=3 6x-3y=5

Solution of system x+y=10,2x+y=18 and 4x-3y=26 is :

2x+3y=3 4x+5y=3

4x-3y=8, 6x-y=29/3

3x-4y=10 , 4x+3y=5

If |[x,x+y, x+y+z],[2x,3x+2y,4x+3y+2z],[3x,6x+3y, 10 x+6y+3z]|=64 , then the real value of x is __________.

If |[x,x+y, x+y+z],[2x,3x+2y,4x+3y+2z],[3x,6x+3y, 10 x+6y+3z]|=64 , then the real value of x is __________.

Find the values of (x+y ) , if (i) 3x + 4y = 11 , 4x + 3y = 10 (ii) 5x - 2y = 4 , x + 8y = 26