If `f(x)={(x^2+5x+lambda)/(x^2-1), x!=1, 7/2,x=1` is continuous at `x=1`, then find the value of `lambda`.

f(x)={[x]+[-x], where x!=2 and lambda where If f(x) is continuous at x=2 then,the value of lambda will be

f(x)={([x]+[x], "when" x ne 2),(lambda, "when" x = 2):} If f(x) is continuous at x = 2, the value of lambda will be

If f(x) = {((1-sinx)/(pi-2x), ",", x != pi/2),(lambda, ",", x = pi/2):} , be continuous at x = (pi)/2 , then the value of lambda is

If f(x) = {((1-sinzx)/(pi-2x), ",", x != pi/2),(lambda, ",", x = pi/2):} , be continuous at x = (pi)/2 , then the value of lambda is

If f(x)={ x^(3)+3x^(2)+lambda x+5 if x =1 is differentiable for all x in R then the value of | lambda-mu| is

If f(x) = {(x+lambda,",",x lt 3),(4,",",x = 3),(3x-5,",",x gt 1):} is continuous at x = 3, then lambda =

If f(x) = {(x+lambda,",",x lt 3),(4,",",x = 3),(3x-5,",",x gt 1):} is continuous at x = 3, then lambda =

Let the function f(x) be defined as below f(x)=sin^(-1) lambda+x^2 when 0 =1 . f(x) can have a minimum at x=1 then value of lambda is

For what value of lambda is the function defined by f(x)={{:(lambda(x^2-2x), ifxlt=0),( 4x+1, ifx >0):} continuous at x = 0 ? What about continuity at x = 1 ?

f(x) = {:([x] + [-x] x ne 2),(" "lambda " " x = 2 ):} f(x) is continuous at x = 2 then lambda =