[(a^(2)+b^(2))/(c)quad c],[aquad (b^(2)+c^(2))/(a)],[bquad bquad (c^(2)+a^(2))/(b)]

If |((a^(2)+b^(2))//c, c, c),(a,(b^(2)+c^(2))//a,a),(b,b,(c^(2)+a^(2))//b)|=k(abc) then k=

Simplify: (a^(2)-(b-c)^(2))/((a+c)^(2)-b^(2))+(b^(2)-(a-c)^(2))/((a+b)^(2)-c^(2))+(c^(2)-(a-b)^(2))/((b+c)^(2)-a^(2))

Prove that |{:((b+c)^(2), a^(2), bc),((c+a)^(2), b^(2), ca),((a+b)^(2), c^(2), ab):}|= (a-b) (b-c)(c-a)(a + b+c) (a^(2) + b^(2) + c^(2)) .

Given, a^(2) =b+c, b^(2)=c + a " & " c^(2) = a + b or (a^(2))/(b+c) = (b^(2))/(c+a) = (c^(2))/(a+b)=1 find (a)/(1+a) + (b)/(1+b) + (c )/(1+c) = ?

Show that , |[(a^2+b^2)/c,c,c],[a,(b^2+c^2)/a,a],[b,b,(c^2+a^2)/b]|=4abc

((a+b)^(2))/((b-c)(c-a))+((b+c)^(2))/((a-b)(c-a))+((c+a)^(2))/((a-b)(b-c))

Show that , |{:((a^2+b^2)/c," "c," "c),(" "a,(b^2+c^2)/a," "a),(" "b," "b,(c^2+a^2)/b):}|=4abc

(cos ^(2) ((B-C)/( 2)) )/( (b+c)^(2))+( sin ^(2)((B-C)/( 2)) )/( (b-c)^(2))=