(1)/(1.3)+(1)/(3.5)+(1)/(5.7)+....." upto "n" terms is- "

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(1)/(1 . 3)+(1)/(3 . 5)+(1) /(5 . 7)+.. to n terms =

(1)/(1.3) + (1)/(3.5) + (1)/(5.7) + …. (n-3) terms

(1)/(1.3)+(1)/(3.5)+(1)/(5.7)+....(n-1)terms

(1)/(3.5)+(1)/(5.7)+(1)/(7.9)+…….. up to n terms is equal to

Find the sum to n terms of the series: (1)/(1.3)+(1)/(3.5)+(1)/(5.7)+...

Find the sum of the series to n terms and to infinity : (1)/(1.3)+ (1)/(3.5) +(1)/(5.7) +(1)/(7.9)+...

(1)/(2*5)+(1)/(5*8)+(1)/(8*11)+ … upto n terms =

The sum of 1+(2)/(5)+(3)/(5^(2))+(4)/(5^(3))+.... upto n terms

The sum of (3)/(1^(3))+(5)/(1^(3)+2^(3))+(7)/(1^(3)+2^(3)+3^(3))+...... upto 11 terms is equal to

underset(n to oo)lim {(1)/(1.3)+(1)/(3.5)+(1)/(5.7)+.....+(1)/((2n-1)(2n+1))}=