To obtain `3 mF` capacity from three capacitors of `2mF` each, they will be arranged

Figure shows a part of a bigger circuit. The capacity of the capacitor is 6 mF and is desaesing at the constate rate 0.5 mF s^(-1) . The potential difference across the capacitor at the shows moment is changing as follows: (dV)/(dt) = 2 V s^(-1) , (d^(2)V)/(dt^(2)) = (1)/(2) V S^(-2) The current in the 4 Omega resistor is decreasing at the rate of 1 mA s^(-1) . What is the potential difference (in mV ) across the inductor at this moment?

Figure shows a part of a bigger circuit. The capacity of the capacitor is 6 mF and is desaesing at the constate rate 0.5 mF s^(-1) . The potential difference across the capacitor at the shows moment is changing as follows: (dV)/(dt) = 2 V s^(-1) , (d^(2)V)/(dt^(2)) = (1)/(2) V S^(-2) The current in the 4 Omega resistor is decreasing at the rate of 1 mA s^(-1) . What is the potential difference (in mV ) across the inductor at this moment?

How will you connect three capacitors to obtain the maximum charge storage capacity?

Raju found that capacity of a parallel plate air capacitor is 10mF. Find the capacity of it when he immersed the unit completely in a medium of dielectric constatn 2.5

Three condensers of same capacity connected in series has effective capacity 2mF. If they are connected in parallel and charged using a battery of emf 12V, the total energy stored in the combination is