{-13-(-27)}+{-25-(-40)}

{20-(25-33)"-:)(-5xx4-(-6)}+56-:(-27+13)=?

Evaluate the sum: 13(15)/(27)+12(14)/(27)

Calculate the mean and S.D for the following data: Expenditure (in Rs.) 0-10 10-20 20-30 30-40 40-50 Frequency: 14 13 27 21 15

If the mean of the following distribution is 27, find the value of p . Class: 0-10 10-20 20-30 30-40 40-50 Frequency: 8 p 12 13 10

If the mean of the following distribution is 27, find the value of p . Class: 0-10 10-20 20-30 30-40 40-50 Frequency: 8 p 12 13 10

Simplify each of the following: 25-1/2{5+4-(3+2- 1+3)} 27-[38-{46-(15- 13-2)}]

Given below are the marks obtained by 32 students in an examination : {:(29 23 30 40 11 01 15 35),(40 03 12 18 30 24 25 29),(31 32 25 22 27 12 13 02),(07 09 19 13 32 39 25 03):} Taking class intervals 1 - 10, 11 - 20............... 31 - 40, make a frequency table for the above distribution.

Fill in the blank in the given nuclear reaction : _______ +""_(13)^(27)Al to""_(12)^(25)Mg+""_(2)^(4)He

The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separartion energy of the nuclei ._(20)Ca^(41) and ._(13)Al^(27) form the following data : m(._20Ca^(40))=39.962591u and m(._(20)Ca^(41))=40.962278u m(._(13)Al^(26))=25.986895u and m(._(13)Al^(27))=26.981541u

The neutron separation energy is defined to be the energy required to remove a neutron form nucleus. Obtain the neutron separation energy of the nuclei ._(20)Ca^(41) and ._(13)Al^(27) from the following data : m(._20Ca^(40))=39.962591u and m(._(20)Ca^(41))=40.962278u m(._(13)Al^(26))=25.986895u and m(._(13)Al^(27))=26.981541u