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CH,CH(OH)COOH" molecule shows."...

CH,CH(OH)COOH" molecule shows."

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Lactic acid, CH_3CH(OH)COOH molecule shows:

CH_(3)CH(OH)COOH molecule shows:

(A): CH_(3)CH(OH)COOH is optically active (R) : CH_(3)CH(OH)COOH do not possess any element of symmetry. The correct answer is

In the reaction : CH_3CHO+HCN to CH_3 CH(OH)CN overset(H.OH)to CH_3 CH(OH)COOH an asymmetric centre is generated. This acid obtained would be :

IUPAC name of, CH_3CH(OH)CH_2CH_2COOH is:

The correct IUPAC name of CH_3 CH(OH)CH_2CH_2COOH is