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For the first order reaction, the taken ...

For the first order reaction, the taken to reduce the initial concentration to a factor of `1/4` is 10 minutes if the reduction in concentration is carried out to a factor of `1/16`, then time required will be

A

10 minutes

B

20 minutes

C

40 minutes

D

60 minutes

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The correct Answer is:
To solve the problem, we will use the first-order reaction kinetics formula. The formula for a first-order reaction is given by: \[ k = \frac{2.303}{t} \log \left( \frac{a}{a - x} \right) \] Where: - \( k \) is the rate constant, - \( t \) is the time, - \( a \) is the initial concentration, - \( x \) is the change in concentration. ### Step 1: Determine the rate constant \( k \) Given that the time taken to reduce the concentration from \( a \) to \( \frac{a}{4} \) is 10 minutes, we can set up the equation: - Initial concentration \( a \) - Final concentration \( a - x = \frac{a}{4} \) Thus, \( x = a - \frac{a}{4} = \frac{3a}{4} \). Substituting into the formula: \[ k = \frac{2.303}{10} \log \left( \frac{a}{\frac{a}{4}} \right) \] This simplifies to: \[ k = \frac{2.303}{10} \log(4) \] Calculating \( \log(4) \): \[ \log(4) = 2 \log(2) \approx 2 \times 0.301 = 0.602 \] So, \[ k = \frac{2.303}{10} \times 0.602 \approx 0.138 \, \text{min}^{-1} \] ### Step 2: Calculate the time for reduction to \( \frac{a}{16} \) Now we need to find the time taken to reduce the concentration from \( a \) to \( \frac{a}{16} \). Here, \( a - x = \frac{a}{16} \), thus \( x = a - \frac{a}{16} = \frac{15a}{16} \). Using the first-order kinetics formula again: \[ t = \frac{2.303}{k} \log \left( \frac{a}{\frac{a}{16}} \right) \] This simplifies to: \[ t = \frac{2.303}{k} \log(16) \] Calculating \( \log(16) \): \[ \log(16) = 4 \log(2) \approx 4 \times 0.301 = 1.204 \] Now substituting \( k \): \[ t = \frac{2.303}{0.138} \times 1.204 \] Calculating \( t \): \[ t \approx \frac{2.303 \times 1.204}{0.138} \approx \frac{2.775}{0.138} \approx 20.1 \, \text{minutes} \] ### Final Answer The time required to reduce the concentration to a factor of \( \frac{1}{16} \) is approximately **20.1 minutes**. ---
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