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For the reaction , N2O4(g)underset(K2)o...

For the reaction , `N_2O_4(g)underset(K_2)overset(K_1)hArr2NO_2(g)`, the rate of disappearance of `NO_2` will be

A

`K_1[N_2O_4]-K_2[NO_2]^2`

B

`2K_1[N_2O_4]-2K_2[NO_2]^2`

C

`K_2[NO_2]^2-K_1[N_2O_4]`

D

`2K_2[NO_2]^2-2K_1[N_2O_4]`

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To find the rate of disappearance of \( \text{NO}_2 \) for the reaction \( \text{N}_2\text{O}_4(g) \underset{K_2}{\overset{K_1}{\rightleftharpoons}} 2\text{NO}_2(g) \), we can follow these steps: ### Step 1: Write the Reaction and Identify the Rate Expressions The reaction can be represented as: \[ \text{N}_2\text{O}_4(g) \underset{K_2}{\overset{K_1}{\rightleftharpoons}} 2\text{NO}_2(g) \] The forward reaction has a rate constant \( K_1 \) and the backward reaction has a rate constant \( K_2 \). ### Step 2: Define the Rate of Disappearance of \( \text{NO}_2 \) The rate of disappearance of \( \text{NO}_2 \) is defined as: \[ -\frac{d[\text{NO}_2]}{dt} \] This negative sign indicates that the concentration of \( \text{NO}_2 \) is decreasing over time. ### Step 3: Write the Rate Expressions for Both Reactions For the forward reaction: \[ \text{Rate}_{\text{forward}} = K_1 [\text{N}_2\text{O}_4] \] For the backward reaction: \[ \text{Rate}_{\text{backward}} = K_2 [\text{NO}_2]^2 \] ### Step 4: Determine the Net Rate of Change of \( \text{NO}_2 \) The net rate of change of \( \text{NO}_2 \) will be the difference between the rate of formation from the forward reaction and the rate of consumption from the backward reaction: \[ \frac{d[\text{NO}_2]}{dt} = 2K_1 [\text{N}_2\text{O}_4] - 2K_2 [\text{NO}_2]^2 \] ### Step 5: Express the Rate of Disappearance of \( \text{NO}_2 \) To find the rate of disappearance of \( \text{NO}_2 \), we take the negative of the net rate: \[ -\frac{d[\text{NO}_2]}{dt} = -\left(2K_1 [\text{N}_2\text{O}_4] - 2K_2 [\text{NO}_2]^2\right) \] This simplifies to: \[ -\frac{d[\text{NO}_2]}{dt} = 2K_2 [\text{NO}_2]^2 - 2K_1 [\text{N}_2\text{O}_4] \] ### Final Answer Thus, the rate of disappearance of \( \text{NO}_2 \) is: \[ -\frac{d[\text{NO}_2]}{dt} = 2K_2 [\text{NO}_2]^2 - 2K_1 [\text{N}_2\text{O}_4] \]
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