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For this reaction N(2(g))+3H(2(g))t...

For this reaction
`N_(2(g))+3H_(2(g))to2NH_(3(g))`
The relation between `(d(NH_(3)))/(dt)` and `-(d(H_(2)))/(dt)` is :-

A

`(d[NH_3])/(dt)=-1/3(d[H_2])/(dt)`

B

`+(d[NH_3])/(dt)=-2/3(d[H_2])/(dt)`

C

`+(d[NH_3])/(dt)=-3/2(d[H_2])/(dt)`

D

`(d[NH_3])/(dt)=(d[H_2])/(dt)`

Text Solution

Verified by Experts

The correct Answer is:
B
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