Home
Class 9
MATHS
In triangleABC, AD is the perpendicular ...

In `triangleABC, AD` is the perpendicular bisector of BC. Show that `triangleABC` is an isosceles triangle in which AB = AC.

Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    CPC CAMBRIDGE PUBLICATION|Exercise EXERCISE 5.3|5 Videos

  • TRIANGLES

    CPC CAMBRIDGE PUBLICATION|Exercise EXERCISE 5.4|6 Videos

  • TRIANGLES

    CPC CAMBRIDGE PUBLICATION|Exercise EXERCISE 5.5 (Optional)|4 Videos

  • SURFACE AREAS AND VOLUMES

    CPC CAMBRIDGE PUBLICATION|Exercise EXERSICE 13.8|10 Videos

Similar Questions

Explore conceptually related problems

In Delta ABC , AD is the perpendicular bisector of BC. Show that Delta ABC is an isoscelss tringle in which AB = AC.

In DeltaABC , AD is the perpendicular bisector of BC (See adjacent figure). Show that DeltaABC is an isosceles triangle in which AB = AC.

DeltaABC is an isosceles triangle in which AB = AC. Show that /_ B = /_ C.

In DeltaABC , the bisector AD of A is perpendicular to side BC Show that AB = AC and DeltaABC is isosceles.

ABC is an isosceles triangle with AB = AC. Draw AP _|_ BC to show that A = B.

AD and BC are equal perpendiculars to a line segment AB. Show that CD bisects AB.

AD and BC are equal and perpendiculars to a line segment AB. Show that CD bisects AB.

triangleABC and triangleDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that: (i) triangleABD ~= triangleACD (ii) triangleABP ~= triangleACP (iii) AP bisects angleA as well as angleD (iv) AP is the perpendicular bisector of BC.

In an equilateral triangle ABC, AD is drawn perpendicular to BC meeting BC in A Prove that AD^(2) = x BD^(2) Find x.