Diagonals AC of a parallelogram ABCD bisects `angleA`. Show that
it bisects `angleC` also

ABCD is a rhombus

Diagonal AC of a parallelogram ABCD bisects A. Show that it bisects C also

Diagonal AC of a parallelogram ABCD bisects A. Show that ABCD is a rhombus.

If the diagonals of a parallelogram are equal, show that it is a rectangle.

If the diagonals of a parallelogram are equal, then show that it is rectangle .

The diagonal AC of a parallelogram ABCD intersects DP at the point Q, where ‘P’ is any point on side AB. Prove that CQ xx PQ = QA xx QD .

The diagonal BD of parallelogram ABCD intersect AE at F as shown in the figure. If E is any point on BC, then prove that DFxxEF=FB=FA .

In the adjacent figure ABCD is a parallelogram ABEF is a rectangle show that DeltaAFD~=DeltaBEC .

ABCD is a rectangle in which diagonals AC bisects angleA as well as angleC , Show that ABCD is a square diagonal BD bisects angleB as well as angleD

In a parallelogram ABCD, the bisectors of the consecutive angles angleA and angleB intersect at P. Show that angleAPB=90^(@) .

Diagonals AC and BD of a quadrilateral ABCD each other at P. Show that ar (APB) xx ar (CPD) =ar (APD) xx ar (BPC)