ABCD is a rhombus Show that diagonal AC bisects `angleA` as well as `angleC` and diagonal BD bisects `angleB` as well as `angleD`.

ABCD is a rhombus. Show that diagonal AC bisects A as well as C and diagonal BD bisects B as well as D.

ABCD is a rectangle in which diagonals AC bisects angleA as well as angleC , Show that ABCD is a square diagonal BD bisects angleB as well as angleD

ABCD is a rectangle in which diagonal AC bisects A as well as C. Show that : ABCD is a square

triangleABC and triangleDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that: (i) triangleABD ~= triangleACD (ii) triangleABP ~= triangleACP (iii) AP bisects angleA as well as angleD (iv) AP is the perpendicular bisector of BC.

ABCD is a rhombus. Prove that AC^(2) + BD^(2) = 4 AB^(2)

Diagonals AC of a parallelogram ABCD bisects angleA . Show that it bisects angleC also ABCD is a rhombus

ABCD is a parallelogram, with AC, BD as diagonals. Then vec AC - vec BD =

ABC is a right triangle in which angleA = 90^(@) and AB = AC. Find angleB and angleC .

Show that the diagonals of a square are equal and bisect each other at right angles.

Show that the diagonals of a square are equal and bisect each other at right angles.