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A table clock has its minute hand 5.0 c...

A table clock has its minute hand ` 5.0 cm` long. Find the average velocity of the tip of the miute hand (a) between ` 6.000 a.m. ` to 6. 15 a.m. and (b) between ` 6.00 a.m. to 6.30. p.m.`

Text Solution

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At 6.00 a.m the tip of the minute hand is at 12 mark and at 6.15 a.m. it is `90^(@)` away.
Thus displacement `= sqrt(R^(2) +R^(2)) =sqrt(2) R =sqrt(2) xx5 cm`
Time taken from 6.00 a.m to 6.15 a.m is 15 minute `= 15 xx 60 s`
Average velocity `=("displacement")/("time taken") =(sqrt(2)xx5)/(15xx60) =7.83 xx10^(-3) cm s^(-1)`
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