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A particles starts from rest and has an...

A particles starts from rest and has an acceleration of ` 2m//s^(2)` for 10 sec. After that , it travels for 30 sec with constant speed and then undergoes a retardation of ` 4m//s^(2)` and comes back to rest. The total distance covered by the particle is

Text Solution

Verified by Experts

Here, `u = 0, a = 2 ms^(–2), t = 10 s" Using "v = u +" at "= 0 +2 xx 10 = 20" ms"^(–1)`
For next `t = 30 s, v = 20" ms"^(–1)` and finally the particle comes to rest in next 5s.
`because" "v=u + at" or "0=20-4t" or "t=5s`
Now, distance = Area of the trapezium OABC
`=(1)/(2) xx (30+45) xx20 =750 m`
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